3x^2+((18/2)x)-12=0

Solution for 3x^2+((18/2)x)-12=0 equation:

3x^2+((18/2)x)-12=0


Domain of the equation: 2)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3x^2+(9x)-12=0

We add all the numbers together, and all the variables

3x^2+9x-12=0

a = 3; b = 9; c = -12;
Δ = b2-4ac
Δ = 92-4·3·(-12)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-15}{2*3}=\frac{-24}{6}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+15}{2*3}=\frac{6}{6}
=1
$